§ 21.94. Acetaldol.
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/us/cfr/t27/s§ 21.94·A research copy — for the controlling text, always check the official state or federal source. Not legal advice.
(a)Purity. Not less than 90 percent by weight acetaldol as determined by the following method: Dissolve 15 grams of the acetaldol in distilled water and dilute to 1 liter in a volumetric flask. Transfer 5 mL of this solution to a 250 mL glass-stoppered flask containing 25 mL distilled water. Add 25 mL of a freshly prepared 1 percent sodium bisulfite solution. Prepare a blank omitting the acetaldol solution. Place the flasks in a dark place away from excessive heat or cold and allow to stand six hours. Remove flasks and titrate free bisulfite with 0.1 N iodine solution using starch indicator. Percent acetaldol by weight = (mL blank − mL test) × 200 × 0.44 / weight of sample Titrations in excess of 100 percent may be obtained if the sample contains appreciable amounts of acetaldehyde.
(b)Specific gravity at 20 °C. 1.098 to 1.105.
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§ 21.94
Acetaldol.
Fed. Reg.×1
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